odd count right and bottom matrix

r,c=map(int,input().split())

l=[list(map(int,input().split())) for i in range(r)]

ans=0

for i in range(r):

    for j in range(c):

        if (i>=r//2 or j>=c//2 )and l[i][j]%2:

            ans+=1

print(ans)